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Wittaler [7]
3 years ago
8

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=29°, and QO = 26 feet. Find the length of PQ to the nearest tenth of a foot.​

Mathematics
1 answer:
noname [10]3 years ago
5 0

Answer:

SOH-CAH-TOA

x=14.412

x=14.412≈14.4 feet

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Through: (-5, -3), perp. to y=-9/4x-5
Mrrafil [7]

Given:

A line passes through (-5,-3) and perpendicular to y=-\dfrac{9}{4}x-5.

To find:

The equation of the line.

Solution:

We have,

y=-\dfrac{9}{4}x-5

On comparing this equation with slope intercept form, i.e., y=mx+b, we get

m_2=-\dfrac{9}{4}

It means, slope of this line is -\dfrac{9}{4}.

Product of slopes of two perpendicular lines is always -1.

m_1\times m_2=-1

m_1 \times \left(-\dfrac{9}{4}\right)=-1

m_1=\dfrac{4}{9}

Slope of required line is \dfrac{4}{9} and it passes through the point (-5,-3). So, the equation of the line is

y-y_1=m(x-x_1)

where, m is slope.

y-(-3)=\dfrac{4}{9}(x-(-5))

y+3=\dfrac{4}{9}(x+5)

9(y+3)=4(x+5)

9y+27=4x+20

27-20=4x-9y

7=4x-9y

Therefore, the equation of required line is 4x-9y=7.

8 0
3 years ago
Fifteen minutes past eight in the evening on a 24 hour clock​
anastassius [24]

Answer: The time is 20:15 on a military time clock.

Step-by-step explanation:

4 0
3 years ago
Please help with this ​
aleksandrvk [35]
Ayooo I can’t do school work either.
5 0
3 years ago
What does 21÷3+(3×9)×9+5 equal? show work below plz
igor_vitrenko [27]
3x9=27
21/3 = 7
so
7+27x9+5
27x9=243
243+7+5
answer is 255
6 0
3 years ago
Read 2 more answers
Combine like terms and simplify 4r - 6 - 2r + 5
murzikaleks [220]
C. 10r-3


Because 2r+5=7, the minus 6 and 7 which gives you 1 then minus 4 and 1 witch is 3 then you do 10r-3 and it will get you to 2r+5=7 again. I hope this helped!
4 0
3 years ago
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