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3 years ago

HELP PLEASE NOW GUVUDYGYESDTIXJRXZTKXRX

Mathematics

1 answer:

kramer3 years ago

6 0

Answer:

He should cross multiply 90 and 60, and then divide by 100. The answer is 54.

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What is the solution for 2x + 3

Leokris [45]

Answer:

Step-by-step explanation:

you would add the numbers like this 2+3 and that equals 5 but you have to keep the X because theres not another number to combine the 2x with

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3 years ago

What is the distance from 0 to point g on the number line

Iteru [2.4K]

Answer:

Step-by-step explanation:

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3 years ago

The time in new York is 16.45 (EDT).what is the time in brisbane(AEST)which is 14 hours ahead?

elena-s [515]

Answer: 06.45

Explanation: For this problem, it is essential to know that there are 24 hours in a day. With that said, we take our starting time of 16.45 and since we want to know what time it is 14 ahead (addition), we add the two numbers together.

16.45 + 14 = 30.45

Since there are only 24 hours in a day, and we have exceeded that value, we subtract 24.

30.45 - 24 = 06.45

And that is the time in Brisbane.

Alternatively, you can count time in 12-hour format and convert 16.45 to 4.45 pm by subtracting 12.

Knowing your start time is 4.45pm simply add 14 to that (or change the pm to an and add 2 since 14-12=2).

You will again get 6.45am.

Cheers.

7 0

2 years ago

Read 2 more answers

Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

5 0

3 years ago

Find the area and perimeter

Lostsunrise [7]

Answer:

AREA=100

Step-by-step explanation:

8 0

3 years ago

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