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3 years ago

A number c is less than 5 and greater than or equal to -2. Write and graph the inequality.

Mathematics

1 answer:

UkoKoshka [18]3 years ago

5 0

Answer:

5>c<_ -2

c can be 4 ,3 ,2 ,1 ,0 ,-1 ,-2

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vredina [299]

Answer:

6 is 56.25

7 is 97.50

Step-by-step explanation:

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4 years ago

Geraldine is picking a four-digit password by using the digits 0 through 9. She can use each digit only once. How many different

Archy [21]

0-9 = 10 numbers

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2nd digit can be 1 of 9

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4th digit can be 1 of 7

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3 years ago

Read 2 more answers

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

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3 years ago

What is the solution for 2t<5

aliya0001 [1]

T < 5/2
t is less than 5/2 or 2.5

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4 years ago

A certain rock has a density of 12.5 g/mL. What volume will 4.0g of this rock occupy

Anon25 [30]

Answer:

0.32 mL

Step-by-step explanation:

d = m/v

v = m/d

v = 4.0 g ÷ 12.5 g/mL

g ÷ g cancels out the unit g

v = 0.32 mL

4 0

4 years ago