Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
<u>Hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>:</u><u>)</u>
Answer:
b. g(x)=|x+3|-1
Step-by-step explanation:
<u>Answer:</u>
H(G(x)) = 12x - 52
<u>Step-by-step explanation:</u>
We are given the following two functions:
And we are to find the value of H(G(x)).
For that, we will apply the function of H on the function of G.
H(G(x)) = 12x - 52
