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svet-max [94.6K]
3 years ago
12

Nine students Ryan’s class are wearing gray there are 30 students in his class Ryan says that 30% of his class is wearing gray i

s he correct explain your reasoning
Mathematics
2 answers:
matrenka [14]3 years ago
7 0

Answer:

Step-by-step explanation:

No u

aleksklad [387]3 years ago
3 0

Answer:

ur mom

Step-by-step explanation:

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The average length of a field goal in the National Football League is 38.4 yards, and the s. d. is 5.4 yards. Suppose a typical
Tasya [4]

Answer:

a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b) 0.25% probability that his average kicks is less than 36 yards

c) 0.11% probability that his average kicks is more than 41 yards

d-a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

d-b) 1.32% probability that his average kicks is less than 36 yards

d-c) 0.80% probability that his average kicks is more than 41 yards

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 38.4, \sigma = 5.4, n = 40, s = \frac{5.4}{\sqrt{40}} = 0.8538

a. What is the distribution of the sample mean? Why?

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b. What is the probability that his average kicks is less than 36 yards?

This is the pvalue of Z when X = 36. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{0.8538}

Z = -2.81

Z = -2.81 has a pvalue of 0.0025

0.25% probability that his average kicks is less than 36 yards

c. What is the probability that his average kicks is more than 41 yards?

This is 1 subtracted by the pvalue of Z when X = 41. So

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{0.8538}

Z = 3.05

Z = 3.05 has a pvalue of 0.9989

1 - 0.9989 = 0.0011

0.11% probability that his average kicks is more than 41 yards

d. If the sample size is 25 in the above problem, what will be your answer to part (a) , (b)and (c)?

Now n = 25, s = \frac{5.4}{\sqrt{25}} = 1.08

So

a)

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

b)

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{1.08}

Z = -2.22

Z = -2.22 has a pvalue of 0.0132

1.32% probability that his average kicks is less than 36 yards

c)

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{1.08}

Z = 2.41

Z = 2.41 has a pvalue of 0.9920

1 - 0.9920 = 0.0080

0.80% probability that his average kicks is more than 41 yards

4 0
3 years ago
A ball is thrown with an initial velocity of 32 ft/s from a height of 4.5 feet. It’s height as a function of time is given by th
Lana71 [14]

Answer:

the ball will be in the air for possibly 2.5 seconds and it max hieght was 10 ft

Step-by-step explanation:

no clue

6 0
3 years ago
Plz Explain will give Brainliest
FromTheMoon [43]

Answer:

The question is wrong?

Step-by-step explanation:

(x)^2 - 4y + 19

(-8)^2 - 4(-9) + 19

64 + 36 + 19

119

5 0
4 years ago
A garden hose emits 9 quarts of water in 6 seconds how much did the water emit in 10seconds
kolbaska11 [484]

Answer: The  15 quarts water emit in 10 second


Step-by-step explanation:

Given: A garden hose emits 9 quarts of water in 6 second.

To find : how much did the water emit in 10 second.

Explanation:

We are given that

                    In 6 second a garden hose emits water= 9 quarts.

                   In 1 second a garden hose emits water = \frac{9}{6} quarts.

                  In 10 second a garden hose emits water=10×\frac{9}{6} quarts

                     Total water emits in 10 second = 15 quarts.

Therefore, the  15 quarts water emits in 10 second.

6 0
3 years ago
Read 2 more answers
Find the equation of the line passing
Ostrovityanka [42]

Answer:

  y = 4x -14

Step-by-step explanation:

The required answer form is slope-intercept form, so we need the slope and the y-intercept of the line.

The slope equation is ...

  m = (y2 -y1)/(x2 -x1)

  m = (10 -2)/(6 -4) = 8/2 = 4

The y-intercept equation is ...

  b = y - mx

  b = 2 -4(4) = -14

The equation of the line is y = 4x -14.

7 0
3 years ago
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