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storchak [24]
2 years ago
7

Which graph shows the solution set for -5/2x -3<2 ​

Mathematics
2 answers:
ollegr [7]2 years ago
5 0

Answer:

Is there supposed to be a photo? Or attachment?

Step-by-step explanation:

madam [21]2 years ago
4 0

Answer:

D

Step-by-step explanation:

I took the quiz!

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I need help on this question
Olegator [25]

Good luck I’m actually looking for answers just like this

6 0
3 years ago
1) When graphing a line from an equation, the first point to plot is the ​
Dafna1 [17]

Answer:

y-intercept (b)

Step-by-step explanation:

If you are working with a slope-intercept equation, that is

y = mx + b

Then you want to put the y-intercept on the graph first. It is the b in the equation it is often at the end of the equation. It is the number that is NOT right next to the x.

Then use the slope (the m, that IS right next to the x) to find the next point. Slope is like directions from one point to another.

Then you can draw the line.

6 0
2 years ago
What value of r is a solution to this equation 5r=15
Vilka [71]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the slope of the line that contains the points (-6,-2) and (3,-2)
ruslelena [56]
Slope = (y2 - y1)/(x2 - x1) = (-2 - (-2))/(3 - (-6)) = (-2 + 2)/(3 + 6) = 0/9 = 0

Required slope = 0
3 0
3 years ago
The equation of a circle is ( x - 3) 2 + ( y + 2) 2 = 25. The point (8, -2) is on the circle.
Shtirlitz [24]

Answer:

x =8 is the equation of the tangent.

Step-by-step explanation:

Here the equation of the given circle is: (x-3)^{2}  + (y+2)^{2}  = 25

Now, comparing it with the general equation of circle: (x-h)^{2}  + (y -k)^{2}  = r^2

we get the central coordinates (h,k)  = (3,-2)

So, the slope of the line joining center and (8, -2) = \frac{-2 -(-2)}{8-3} = \frac{0}{5} = 0

Since the slope of line = 0, line is parallel to x axis.

Now, as tangent and the line is perpendicular to each other

⇒Slope of the tangent = -1/ slope of the line = \frac{-1}{0}

Now, by point slope formula: the equation of the tangent is

(y-y0)  = m (x-x0)

or, (y +2) = \frac{-1}{0} (x -8)

or x =8 is the equation of the tangent.

8 0
3 years ago
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