Answer:
It looks the same but it can be smaller or big and they both look the same shape.
Step-by-step explanation:
For this case we must find the value of the variable "x" of the following equation:

We multiply by 3 on both sides of the equation:

We divide between 2 on both sides of the equation:

We subtract 7 on both sides of the equation:

Answer:
Option B
Point slope is y-y1=m(x-x1)
Keep y and x as they are (do not plug anything in for those).
Variable m is the slope.
x1 and y1 are part of the point, which is in (x, y) form.
With the information given, plug each into the equation.
m= 2 (It's the slope)
x1=-8
y1=5
Put these variables into the equation like this-
y-5=2(x--8)
The two negatives cancel out (between x and 8) so your final answer is-
y-5=2(x+8)
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.