Determine the value for b assuming that the two horizontal lines displayed are parallel.

Plz help/ Trigonometric models and sine functions: plz show how you got and the GRAPH! Thx to anyone that can help

Shtirlitz [24]

Answer:

$y=-2\sin(2x)-2$ - The graph is attached below.

Step-by-step explanation:

Given : A sine function has the following key features:

Period = π , Amplitude = 2, Midline: y = -2 , y-intercept: (0,-2)

The function is a reflection of its parent function over the x-axis.

To plot the graph :

Solution :

General form of sin function is $y=A sin(Bx)+C$

Where A is the amplitude

$B=\frac{2\pi}{\text{Period}}$

C is the midline

Substitute the given key features

A=2 , C=-2

$B=\frac{2\pi}{\pi}=2$

The sin function is $y=2\sin(2x)-2$

The function is a reflection of its parent function over the x-axis.

i.e, The coordinate became (x,y)→(x,-y)

The sin function is $y=-2\sin(2x)-2$

Now, We plot the graph of the sin function.

The graph is attached below.

First point is midline i.e, (0,-2)

Minimum point is $(\frac{\pi}{4},-4)$

7 0

3 years ago

Read 2 more answers

Help!!! Carla earns $6.25 per hour working at a store. When she gets her paycheck she repays her brother $40. She has at least $

lora16 [44]

What i did was add 40 to 120 to get 160. then i devided 160 by the 6.25 she got per hour and i got 25.6 and rounded to 26 which would end up being the least amount of hours she could’ve worked. so 26 is the answer i’m pretty sure

4 0

3 years ago

When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the future value FV.

In order to see the rule of formation, let's see the value (in $) for the first few years

End of year 0

1,000

End of year 1(capital + interest + new deposit)

1,000*(1.09)+10

End of year 2 (capital + interest + new deposit)

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

End of year 3 (capital + interest + new deposit)

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the sum of a geometric sequence with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The present value PV is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

3 years ago

The two triangles in the following figure are congruent. What is m< B

balu736 [363]

Answer:

37°

Step-by-step explanation:

Sum of angles in a triangle = 180°

So 96 + 47 = 143

180 - 143 = 37

5 0

3 years ago

sean lives about 15.5 miles from the airport which number rounds to 15.5 when ronded to nearest tenth

goldfiish [28.3K]

16.0Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers