A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.
C) The probability the golfer got six holes-in-one during a single game is close to 0%.
<h2 /><h2><u>How to determine probabilities</u></h2>
Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:
- 1 - 0.12 = 0.88
- 0.88 ^ 17 = 0.1138
- 0.88 ^ 18 = 0.1001
Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
- 0.88 ^ 18 - 0.12 ^ 2 = X
- 0.0857 = X
Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.
- 0.12 ^ 6 x 0.88 ^ 12 = X
- 0.0000000001 = X
Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.
Learn more about probabilities in brainly.com/question/25273534
Answer:
<em>37.3° </em>
Step-by-step explanation:
sin β = 
⇒ β = arcsin = <em>37.3°</em>
we have: -10/4 = -2.5 ⇒ -2 > -2.5 > -3
ANSWER : -2 and -3
ok done. Thank to me :>
Answer:
3600 ways
Step-by-step explanation:
person A has 7 places to choose from :
→ He has 2 places ,one to the extreme left of the line ,the other to the extreme right of the line
If he chose one of those two ,person B will have 5 choices and the other 5 persons will have 5! Choices.
⇒ number of arrangements = 2×5×5! = 1 200
→ But Person A also , can choose one of the 5 places in between the two extremes .
If he chose one of those 5 ,person B will have 4 choices and the other 5 persons wil have 5! Choices.
⇒ number of arrangements = 5×4×5! = 2 400
In Total they can be arranged in :
1200 + 2400 = 3600 ways
