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3 years ago

Brainliest to correct answer first!

Mathematics

1 answer:

Shalnov [3]3 years ago

7 0

Answer: Choice B (i)

Step-by-step explanation:

i stands for an imaginary number, and it will always be one. Even if I is in the power of 3, it still stays as an imaginary number.

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What are the names of the two angles? *

Vika [28.1K]

Answer:

C or the 3rd one

Step-by-step explanation:

7 0

3 years ago

Solve the system: 2x+6y=36 x+4y=20

Assoli18 [71]

Let's solve this problem step-by-step

Let's set:

2x + 6y = 36 -- equation 1

x + 4y = 20 -- equation 2

(equation 2) * 2

2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

2y = 4

y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

x + 4(2) = 20

x = 20 - 8

x = 12

Thus x = 12 and y = 2

Let's check, by substituting these values

$2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20$

Answer: x = 12 and y = 2

Hope that helps!

5 0

3 years ago

Helppppppppopopoppppp

skelet666 [1.2K]

Answer:

DG = 30

Step-by-step explanation:

Given:

DH = 6

DE = 4

EF = 16

Required:

Solution:

DG = DH + HG

DG = 6 + HG

Let's find HG

Given that HE is parallel to the third side of ∆DGF, based on the side-splitter theorem, the other two sides of ∆DGF are divided proportionally.

Therefore,

DH/HG = DE/EF

6/HG = 4/16

Cross multiply

HG*4 = 16*6

HG = 96/4

HG = 24

✔️DG = 6 + HG

DG = 6 + 24

DG = 30

7 0

3 years ago

Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .