we know that
The scalar magnitude of the velocity vector is the speed. The speed is equal to

in this problem we have

substitute in the formula


therefore
<u>the answer Part a) is</u>
the speed is equal to 
<u>Part b) </u>Find the velocity
we know that
<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it
in this problem we have
the magnitude is equal to the speed


therefore
<u>the answer Part b) is</u>
the velocity is 
Part c)
we know that
the acceleration is equal to the formula

in this problem we have


substitute in the formula



therefore
<u>the answer Part c) is</u>
the acceleration is 
This is an example of negative acceleration
9514 1404 393
Answer:
59°
Step-by-step explanation:
Opposite angles of an inscribed quadrilateral are supplementary.
∠N +∠L = 180°
(a +16) +(a -18) = 180
2a = 182 . . . . . . . . . . add 2
a = 91 . . . . . . . . . . . . divide by 2
Then the measure of angle M is ...
∠M = (a+30)° = (91 +30)° = 121°
and angle K is its supplement.
∠K = 180° -121°
∠K = 59°
22/3 sorry I accidentally deleted steps
Answer:
-48
Step-by-step explanation:
Answer:
x = 20 degrees
Explanation:
With a 20 degree angle on the direct opposite side, it shows that x is also 20 degrees; and the other two angles would be 160 degrees.
Hope this helps :)