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Schach [20]
3 years ago
13

Which graph does not represent a function?

Mathematics
1 answer:
Rashid [163]3 years ago
6 0

Answer:

The third one because it fails the vertical line test.

A vertical line would not touch the line more than once at any point on the graph, if it were a function.

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Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall
harina [27]

Answer :

  • 4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

{\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}

\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}

\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}

Therefore,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: the  \: wall = length \times breadth \times height}}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: the  \: wall = 1000 \times 24 \times 400 \:  {cm}^{3} }}}

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: each  \: brick = length \times breadth \times height}}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: each  \: brick = 24 \times 12 \times 8 \:  {cm}^{3} }}}

So,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: bricks  \: required =  \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: bricks  \: required =  \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: bricks  \: required =   \bf \: 4166.6} }}

Therefore,

  • <u>The wall requires 4167 bricks. </u>

6 0
2 years ago
Candy and Tim share a paper route. It takes Candy 85 min to deliver all the papers, and it takes Tim 65 min. How long does it ta
RSB [31]

Answer:

The time required to finish the work by both candy and Tim working together = 36.83 minute

Step-by-step explanation:

Time taken by the candy to finish the work T_{1}= 85 min

Time taken by the Tim to finish the work T_{2}  = 65 min

Thus the time taken by both to finish the work = \frac{T_1 \times\ T_2}{T_1 + T_2}

Put the values of T_{1} and T_{2}  we get ,

                    T_{} = \frac{85 \times\ 65}{85 + 65}

                    T_{} = \frac{221}{6}

                    T_{} = 36.83 minute

Thus the time required to finish the work by both candy and Tim working together = 36.83 minute

3 0
3 years ago
What is 0.65 repeating times 11 over 5​
topjm [15]

Firstly, write out as a number, using a few repeats of the decimal. If we multiply this number by 10 it will give a different number with the same digit recurring. When two digits recur multiply by 100 so that the recurring digits after the decimal point keep the same place value.

4 0
4 years ago
Write a word phrase for each algebraic expression :<br><br> 3x + 10
krek1111 [17]

Answer:

Three times x plus ten.

6 0
3 years ago
Read 2 more answers
will mark first person correct BRAINLIST!!!!!!!!!!!!!!!!the local newspaper has letters to the editor from,70 people. If this nu
Evgen [1.6K]

Answer:

3500

Step-by-step explanation:

2/100=70/?

2*35=70

35*100=3500

6 0
3 years ago
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