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elena-14-01-66 [18.8K]
2 years ago
13

2/11 + 3/5 in it's simplest form​

Mathematics
2 answers:
swat322 years ago
5 0

Answer:

6/55

Step-by-step explanation:

ra1l [238]2 years ago
4 0

Answer:

43/55.

Step-by-step explanation:

\frac{2}{11} +\frac{3}{5}

Step 1: <u>Explain/define.</u>

To add fractions that have different denominators, you must first find the least common multiple (of the denominators).

An easy way to do this is to list the denominators' multiples.

Step 2: <u>Solve.</u>

11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110, 121

5: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55

The smallest number both denominators have in common is 55.

Now, we change both fractions to where they have denominators of 55.

**WHATEVER YOU MULTIPLY THE DENOMINATOR BY, MULTIPLY IT BY THE NUMERATOR AS WELL**

\frac{2}{11} *\frac{5}{5} =\frac{10}{55}

\frac{3}{5} *\frac{11}{11} =\frac{33}{55}

Now, we add the fractions as normal, while keeping the denominators the same.

\frac{10}{55} +\frac{33}{55} =\frac{43}{55}

Step 3: <u>Conclude.</u>

43/55 is already in the simplest form. Therefore, 2/11 + 3/5 = 43/55.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
If the length of a rectangular garden is 2 feet less than the length of a house and the width of the garden is 5 feet less than
Goshia [24]

Answer:

A(h)  =  h²/2 - 6*h + 10

Step-by-step explanation:

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Now if we call "h" the length of the house, we have the following expressions

L = h - 2  and

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The expression for the area f the ectangle as a function of the length of the house is:

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A(h)  = h²/2 - 5*h - h + 10

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Answer:

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Step-by-step explanation:

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