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earnstyle [38]
3 years ago
8

ANSWER ASAP PLEASE FOR BRAINLIEST

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

<h2><em><u>11.2 - B to C</u></em></h2><h2><em><u>12 - B to A</u></em></h2><h2><em><u>8.8 - A to C</u></em></h2>

You have to multiply all the sides by 4.

B to C = 2.8*4

2.8 * 4 = 11.2

B to A = 3*4

3*4 = 12

A to C = 2.2*4

2.2*4 = 8.8

Hope this helped!

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{(-9,3) (5,-6) (3,-1), (-6,5), ?}Which ordered pair can replace the missing value and make the set if ordered pairs NOT a functi
Nookie1986 [14]
\text{Slope}=\frac{-1--6}{3-5}=\frac{5}{-2}\begin{gathered} y-y_1=\frac{5}{-2}(x-x_1) \\  \\ y--6=\frac{5}{-2}(x-5) \\  \\ -2(y+6)=5(x-5) \\ -2y-12=5x-25 \\ 5x+2y=25-12 \\ 5x+2y=13 \end{gathered}

The missing values are (-6, -9) ( The last option)

Explanation:

x= - 6 has already produced the value of y as 5, the only pair in the given option the make the given ordered pairs NOT to be a function is (-6, -9) since it will give the value of y to be - 9.

4 0
1 year ago
Im timed make it quick
erica [24]

Answer:

i think its a

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve for n: 6n+12=6
arlik [135]

Hey there! :)

6n + 12 = 6

Isolate our given variable.

We can do this by subtracting both sides by 12.

6n + 12 - 12 = 6 - 12

Simplify.

6n = -6

Divide both sides by 6.

6n ÷ 6 = -6 ÷ 6

Simplify.

n = -1

~Hope I helped!~

3 0
3 years ago
Read 2 more answers
Suppose a researcher is testing the hypothesis Upper H 0​: pequals0.4 versus Upper H 1​: pless than0.4 and she finds the​ P-valu
andre [41]

Answer:

D. If the​ P-value for a particular test statistic is 0.33​, she expects results at least as extreme as the test statistic in exactly 33 of 100 samples if the null hypothesis is true.

D. Since this event is not​ unusual, she will not reject the null hypothesis.

Step-by-step explanation:

Hello!

You have the following hypothesis:

H₀: ρ = 0.4

H₁: ρ < 0.4

Calculated p-value: 0.33

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

In this case, you have a 33% chance of getting a value as extreme as the statistic value if the null hypothesis is true. In other words, you would expect results as extreme as the calculated statistic in 33 about 100 samples if the null hypothesis is true.

You didn't exactly specify a level of significance for the test, so, I'll use the most common one to make a decision: α: 0.05

Remember:

If p-value ≤ α, then you reject the null hypothesis.

If p-value > α, then you do not reject the null hypothesis.

Since 0.33 > 0.05 then I'll support the null hypothesis.

I hope it helps!

3 0
3 years ago
If 8 measures 119 what is the sum 1 and 4
kompoz [17]
7l5     3l1
8l6     4l2
 Parallel 

8 0
3 years ago
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