Answer:
Therefore the Area of Rhombus ABCD is 36 unit².
Step-by-step explanation:
Given:
ABCD is a Rhombus
A = (-1,0)
B = (5,-3)
C = (-1,-6)
D = (-7 ,-3)
To Find:
Area of Rhombus ABCD = ?
Solution:
We know that Area of Rhombus is given as
Where ,
d₁ and d₂ are the Diagonals.
We have,
Diagonals as AC and BD,
Using Distance Formula we get
Substituting coordinates A and C we get
Similarly for BD we have,
Now Substituting AC and BD in Formula we get
Therefore the Area of Rhombus ABCD is 36 unit².
1. Only true to division. Most likely though when multiplying it's more helpful to have the denominators the same.
2. True
3. False
4. True
Answer:
4 is the answer
Step-by-step explanation:
you can - or + the equation only then when the letter is same z and z both are same so you can - them and get the answer.
Answer:
Step-by-step explanation:
Given
Quadrilateral QRST
Q (1, 2), R (3, 4), S (5, 6), and T (2, 7)
Dlated Factor = 2
Required
Coordinates of quadrilateral Q′R′S′T′
<em>Provided that a quadrilateral is dilated with the center of dilation at the origin; the new dilated shape is simply the multiplication of the dilation factor by the coordinates of the original shape;</em>
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In other words,
Q'R'S'T' = Dilation factor * QRST
When Q = (1,2)
Q' = 2 * (1,2)
Q' = (2,4)
When R = (3,4)
R' = 2 * (3,4)
R' = (6,8)
When S = (5,6)
S' = 2* (5,6)
S' = (10,12)
When T= (2,7)
T' = 2 * (2,7)
T' = (4,14)
Hence, the coordinates of Q'R'S'T' is
Q' = (2,4); R' = (6,8); S' = (10,12); T' = (4,14)
