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3 years ago

Help me Out please I need help

Mathematics

1 answer:

pashok25 [27]3 years ago

3 0

Answer:

So the surface area consists of 2 triangles and 3 different rectangles

Triangle area = 1/2 * 8cm * 6cm = 24cm²

Rectangle a area (bottom one) = 17cm * 8cm = 136cm²

Rectangle b area (the one to the left) = 17cm * 6cm = 102cm²

To calculate Rectangle c we need to know the hypotenuse of our triangles

Formula for the hypotenuse is c = $\sqrt{a^2+b^2}$

so c = $\sqrt{6^2+8^2}$ = 10

Rectangle c area = 17cm * 10cm = 170cm²

So the surface area is 2 * 24cm² + 136cm² + 102cm² + 170cm² = 456cm²

The volume is 1/2 * h * a * b = 1/2 * 6cm * 8cm * 17cm = 408cm³

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4 years ago

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Answer:

La cantidad de dinero adeuda al final de los dos procesos es $1450

Step-by-step explanation:

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La cantidad pagada por la ropa = $2600

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3 years ago

Sonya took out a mortgage of $65,000 at 7% for 25 years. What is the cost of the mortgage?

Vika [28.1K]

The cost of the mortgage is $81250

<h3>What are interests?</h3>

Interests are percentages of a principal

Given the following parameters

Principal = $65000

Rate = 7% = 0.07
Time = 5 years

<h3>Calculate the interest</h3>

I = PRT/100
I = 65000*0.07*25
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<h3>Determine the cost of the mortgage</h3>

Cost of mortgage = Principal + Interest

Cost of mortgage = 65000 + 16250
Cost of mortgage = 81,250

Hence the cost of the mortgage is $81250

Learn more on mortgage here: brainly.com/question/22846480

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3 years ago

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3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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