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Maru [420]
3 years ago
14

When Sam’s little brother was born, he was 18 inches tall. Each year, he grows an average of 3 inches. Sam’s brother continues t

his growth pattern. How many inches tall will he be after 9 years? (Hint: create a table with an independent variable, x, and a dependent variable ,y)
Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0

Answer:

45

Step-by-step explanation:

year 1 : 18 in

every year after that he grows 3 in so 3 in so 3x9=27

then 27+18=45

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Marlon asks a friend to think of a number from 5 to 11. What is the probability that Marlon’s friend will think of the number 9?
Yanka [14]
The answer in fraction form is 1/6
4 0
3 years ago
Which two values of x satisfy the equation square root 3-2cos x = 2?
Andrei [34K]

Answer: x=2π/3 and x=4π/3

Step-by-step explanation:

The equation we have is \sqrt{3-2cosx} =2. All we have to do is get cosine alone to find the 2 values of x.

3-2cosx=4\\-2cosx=1\\cosx=-\frac{1}{2}

Now that we have our cosine left, we can use our unit circle to figure out when does cosx=-1/2. Cosine is the x value of the coordinate.

x=2π/3

x=4π/3

8 0
3 years ago
HELP ASAP PLEASE
telo118 [61]
I’m pretty sure it would be 372.22
5 0
3 years ago
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What is 2.9 as a mixed number?
lapo4ka [179]

Answer:

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3 0
3 years ago
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Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
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