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2 years ago

4. Which expression is a simplified form of -5(8x)? a. 40x b. -40% C. 3x d. -40x?

Mathematics

1 answer:

Sedbober [7]2 years ago

5 0

Answer:

Option d

Step-by-step explanation:

-5(8x)

= -5×8×x

= -40x

Answered by GAUTHMATH

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Can someone help me solve this.

Amanda [17]

Answer:

equilateral: E

scalene: F

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Step-by-step explanation:

equilateral = all sides are equal

scalene = no sides are equal

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3 years ago

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victus00 [196]

Answer:

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Step-by-step explanation:

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3 years ago

(6.253•10^-2)(7.112x10^3) in scientific notation

zlopas [31]

Answer:

4.4471336 * 10^2.

Step-by-step explanation:

(6.253•10^-2)(7.112x10^3)

= 6.253*7.112 * 10^-2*10^3

= 44.471336 * 10^1

= 4.4471336 * 10^2.

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3 years ago

Please answer the question below. please provide an explanation as well. thanks!

Elena-2011 [213]

Answer:

Step-by-step explanation:

Since S is the midpoint of RT, then RS = ST

RS = RT - ST = (3x + 7) - (x + 7) = 3x + 7 - x - 7 = 2x

so we get that RS = 2x

but since RS = ST, and RS=2x & ST=x+7

then 2x = x + 7

2x-x = 7

x = 7

ST = x+7 = 7+7 = 14

P.S. Hope it makes sense. If you have any questions, feel free to ask them in the comments senction. I'll be happy to help. Have a wonderful day!

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2 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago