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Llana [10]
3 years ago
13

If Mitch bicycles at an avenger speed of 18 miles per hour,how long will it take him to cover 76.5 miles?

Mathematics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interes
Vsevolod [243]

Answer:

  • CDs — $10,000
  • bonds — $80,000
  • stocks — $45,000

Step-by-step explanation:

Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:

  c + b + s = 135000 . . . . . . . . . . . . . . . . . total invested

  0.0275c +.045b +0.104s = 8555 . . . . . total income earned

  -c + b = 70000 . . . . . . . . . . . . . . . . . . . . . 70,000 more was in bonds than CDs

Using the third equation to write an expression for b, we can substitute into the other two equations.

  b = 70000 +c . . . . . . . . . . . . . . . . expression we can substitute for b

  c + (70000 +c) +s = 135000 . . . . substitute for b in the first equation

  2c +s = 65000 . . . . . . . . . . . . . . . . [eq4] simplify

  .0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn

  .0725c +.104s = 5405 . . . . . . . . . . [eq5] simplify

Using [eq4], we can write an expression for s that can be substituted into [eq5].

  s = 65000 -2c . . . . . . . expression we can substitute for s

  0.0725c +0.104(65000 -2c) = 5405

  -0.1355c = -1355 . . . . . . . . . . . . . . . . . . . . subtract 6760, simplify

  c = 1355/.1355 = 10,000

  s = 65000 -2×10000 = 45,000

  b = 70000 +10000 = 80,000

The amounts invested in stocks, bonds, and CDs were $45,000, $80,000, and $10,000, respectively.

_____

Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...

\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right]

6 0
3 years ago
how far would a 4.0 cm tall object be located from a reflecting surface with a focal lenght that is equal to 5 cm if it is to cr
katrin [286]

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

Use the mirror equation:

1/di + 1/do = 1/f

where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.)

Substitute and solve for do.

1/do + 1/(-10 cm) = 1/(15 cm)

1/do = 1/(15 cm) - 1/(-10 cm) = 5/(30 cm)

do = 6 cm

Hope it helps you

Regards,

Rachana

5 0
3 years ago
In the united states the speed limit signs are in Miles per hour. Unfortunately, your speedometer only reads in km/hour. How man
ohaa [14]

Hello,

1mph = 1.60934kph

70 x 1.60934 = 112.6538

Answer:

70mph = 112.6538kph

8 0
3 years ago
WILL MARK BRAINLIEST !!!
Finger [1]

Answer:

2:5

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
PLEASE SOLVE AL QUESTIONS, PLEASEEE!!
Nana76 [90]

9514 1404 393

Answer:

  a) 2

  b) left: 3; lower right: 5

  c) upper right: 53°; bottom: 82°

Step-by-step explanation:

<h3>3.</h3>

a) The top side of polygon B is 5 units; the corresponding top side of polygon A is 2.5 units, so the dimensions of polygon A are multiplied by the scale factor 5/2.5 = 2 to give the dimensions of polygon B.

  the scale factor is 2

__

b) Sides of polygon B are 2 times the length of the corresponding side of polygon A.

  left side: 2×1.5 = 3

  lower right side: 2×2.5 = 5

__

c) Corresponding angles of similar figures are congruent.

  upper right angle: 53°

  bottom angle: 82°

___

4.

The arithmetic of problem 4 is correct as shown.

8 0
2 years ago
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