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3 years ago

If Mitch bicycles at an avenger speed of 18 miles per hour,how long will it take him to cover 76.5 miles?

Mathematics

1 answer:

Lisa [10]3 years ago

6 0

Answer:

Step-by-step explanation:

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What are numbers that add to 50 and subtract to 10

sesenic [268]

Answer:

30 plus 20 is 50

30 minus 20 is 10

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2 years ago

M^2-10m+9=(m-9)( ) filling the missing factor to complete the equation

Romashka [77]

Answer:

m-1

Step-by-step explanation:

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3 years ago

You babysit for 3 hours. You receive $24. what is your hourly wage

storchak [24]

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six dollars

Step-by-step explanation:

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2 years ago

The equations in this sytem were added to solve for x. What is the value of x?

son4ous [18]

Question:

The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3

Options:

x = negative 3

x = negative 1

x = 1

x = 3

Answer:

The value of x is 1

Solution:

Given system of equations are:

-2x + y = 8 ------- eqn 1

5x - y = -5 ------- eqn 2

The above equations are added to solve for "x"

Add eqn 1 and eqn 2

-2x + y + 5x - y = 8 - 5

Combine the like terms

-2x + 5x + y - y = 3

Add the like terms

3x + 0 = 3

3x = 3

Divide both sides of equation by 3

x = 1

Thus the value of x is 1

8 0

2 years ago

Read 2 more answers

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

2 years ago