The test That holds true for this inequality is given as 1/4 and 1
<h3>How to solve for the inequality</h3>
3/2 y - 2x > 1
The goal is to make y the subject
then
3/2 y > 2x + 1
We have to divide through the equation by 3/2
Such that y > 4/3 x + 2/3
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Answer:
y = 2/3x - 5 or in standard form 3y = 2x - 5
Step-by-step explanation:
Remember this fact: Parallel lines have the same slope
Step 1 Solve for y so that the equation is in the slope- intersect form
2x - 3y = 6
-3y = -2x + 6
-3y/-3 = -2x/-3 + 6/-3
y = 2/3 x -2
now we know the slope is 2/3 or
when the equation is in Standard form Ax + By = C you can use this fact: slope = - A/B so the slope = -2/-3 = 2/3
Remember the Parallel lines have the same slope
Find the y-intersect "b" use the slope = 2/3 and point (6, -1)
y = mx + b
-1 = 2/3(6) + b
-1 = 4 + b
-5 = b
Now write the equation of line that is parallel to the given line and passes through point (6, -1)
y = 2/3x - 5 or in standard form 3y = 2x - 5
Y=1/2x+2 since the slope is 1/2 and the y intercept is 2
107........,...............
Answer:
In my opinion both of the lines are tangent.
Step-by-step explanation:
Because a tangent to a circle is a straight line which touches the circle at only one point. This point is called the point of tangency. The tangent to a circle is perpendicular to the radius at the point of tangency.
