Look at the pic for the question

Mathematics

1 answer:

vfiekz [6]3 years ago

7 0

Answer:

125.125

hope it help u dear

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Based on the graph, what is the dependent variable, the equation relating the two variables, and how far will the dragonfly trav

ivann1987 [24]

Answer:

<h2>The dependent variable is distance, the equation is y = 20x, and the dragonfly will travel 480 miles.</h2>

Step-by-step explanation:

According to the graph, the dependent variable is Distance in miles, because it's on the vertical axis. Additionally, the independent variable is time in hours, because it's on the horizontal axis. However, you always put time as independent, because nothing affects time.

To find the equation, we just need to find the slope, using two points (0,0) and (2,40).

$m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }=\frac{40-0}{2-0}=20$

Therefore, the equation is $y=20x$ , which shows a direct proportion between variables.

Now, in 24 hours, it would travel

$y=20(24)=480$

It would travel 480 miles.

Therefore, the right answer is the second choice.

8 0

3 years ago

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The student council has decided to have a raffle at the carnival. They came up with a table to show the relationship between the

miskamm [114]

Answer: its just helpful

Step-by-step explanation:

5 0

3 years ago

The figure is a square. Find the length of side x in simplest radical form with a rational denominator.

nika2105 [10]

Answer:

$10\sqrt{2}$

Step-by-step explanation:

The diagonal of any square with side length $s$ is equal to $s\sqrt{2}$ . Since the side length of the square is 10, the diagonal must be $\boxed{10\sqrt{2}}$ .

To support and prove this:

The diagonal creates two 45-45-90 triangles, with the diagonal being the hypotenuse of both of these triangles. The Pythagorean Theorem states that in any triangle, the sum of the squares of both legs is equal to the square of the hypotenuse ( $a^2+b^2=c^2$ ).

Call the diagonal $d$ . In these two triangles, both legs are equal to 10 (the side lengths of the square), and the hypotenuse is the diagonal. Thus, we have: