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Zarrin [17]
3 years ago
13

Can anyone solve this?

Mathematics
2 answers:
Zanzabum3 years ago
6 0
C) The equation can be rewritten as:

\frac{7 * 6!}{6! * 5!} *  \frac{13 * 12 * 11 * 10!}{10!}

6! and 10! in the numerator and denominator cancel out. Leaving you with: 
\frac{7}{5!} * 13 * 12 * 11

Simplify: 
\frac{12012}{120} = 100.1 

d) (2 + 4)! = 6!
6 * 5 * 4 * 3 * 2 * 1
30 * 12 * 2
360 * 2
720

e) Just like in part c, we can rewrite the numerator:
\frac{26 * 25* 24!}{24! * 2!}

The 24! in the numerator and denominator cancel out. Leaving you with:
\frac{26*25}{2*1} =  \frac{650}{2} = 325

f) Just like part c and e, we can rewrite the denominator:
\frac{15! * 8!}{16 * 15!}

15! cancels in both top and bottom. Leaving you with:
\frac{8!}{16} = 2520
sergejj [24]3 years ago
4 0
C) 100.1
D) 720
E) 325
F) 2520
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