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2 years ago

Can anyone solve this?

Mathematics

2 answers:

Zanzabum2 years ago

6 0

C) The equation can be rewritten as:

$\frac{7 * 6!}{6! * 5!} * \frac{13 * 12 * 11 * 10!}{10!}$

6! and 10! in the numerator and denominator cancel out. Leaving you with:
$\frac{7}{5!} * 13 * 12 * 11$

Simplify:
$\frac{12012}{120}$ = 100.1

d) (2 + 4)! = 6!
6 * 5 * 4 * 3 * 2 * 1
30 * 12 * 2
360 * 2
720

e) Just like in part c, we can rewrite the numerator:
$\frac{26 * 25* 24!}{24! * 2!}$

The 24! in the numerator and denominator cancel out. Leaving you with:
$\frac{26*25}{2*1} = \frac{650}{2} = 325$

f) Just like part c and e, we can rewrite the denominator:
$\frac{15! * 8!}{16 * 15!}$

15! cancels in both top and bottom. Leaving you with:
$\frac{8!}{16} = 2520$

sergejj [24]2 years ago

4 0

C) 100.1
D) 720
E) 325
F) 2520

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