The graph for y=4-|x| is shown in the attached picture, the inequality tell us that the region is located below that particular graph including the function, hence you have the second attached picture

6 0

3 years ago

Please help with number 7

DedPeter [7]

Answer:

Step-by-step explanation:

cos 2α=1-2 sin² α

$sin \alpha =\sqrt{\frac{1-cos2\alpha }{2} } \\put~ \alpha =\frac{\pi }{8} \\2\alpha =\frac{\pi }{4} \\cos 2\alpha =cos \frac{\pi }{4}=\frac{1}{\sqrt{2} } \\\\sin(\pi/8)=\sqrt{\frac{1-\frac{1}{\sqrt{2} } }{2}} =\sqrt{\frac{\sqrt{2}-1 }{2\sqrt{2} }$

6 sin 3 \theta+6 sin \theta

$6 sin 3 \alpha +6 sin\alpha =6(sin 3\alpha +sin \alpha )\\=6 *2sin \frac{3\alpha+\alpha }{2} cos \frac{3\alpha-\alpha }{2} \\=12 sin 2\alpha cos \alpha$

please change α to \theta

5 0

3 years ago

A lines slope is 6 and it's y-intercept is 5 what is the equation in slope-intercept form

Soloha48 [4]

Answer:

y=6x+5

Step-by-step explanation:

7 0

3 years ago

What is the solution to the equation 1/4x-1/8=7/8+1/2x?​

What is the solution to the equation 1/4x-1/8=7/8+1/2x?