Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
Step-by-step explanation:
AD = 4
AC = 11
DC = 11 - 4 = 7
First, find BD using the right triangle altitude theorem:
Plug in the values
Use pythagorean theorem to find x:
x² = AD² + BD²
Plug in the values
Take the square root of both sides
Answer:
Good
Step-by-step explanation:
How has been your day?
Answer:
B. 15
Step-by-step explanation:
Prime factors of 15 is 3 and 5
sum of 3 and 5 is 8
