Number like 10 10 1000 and so on are called

We have a study involving 5 different groups that each contain 9 participants (45 total). What two degrees of freedom would we r

vivado [14]

Answer:

Degree of freedoms F(4,40)

Step-by-step explanation:

Given:

There is a study which is involving 5 different groups that each contains 9 participants (totally 45)

The objective is to calculate the degree of freedoms

Formula used:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Solution:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Where,

K= number of groups = 5

N= total number of observations

which is given as follows,

N=45

Then,

Numerator degree of freedom = k-1

=5-1

=4

Denominator degree of freedom = N-K

=45-5

=40

Therefore,

Degree of freedoms, F(4,40)

7 0

3 years ago

Math answer homework

stiv31 [10]

Answer:

2:15 p.m.

Step-by-step explanation:

Starting time 1:40 p.m.

Time on subway +0:17

Time off subway 1:57 p.m.

Time walking +0:18

Time at apartment 1:75

When the minutes are more than 60, you subtract 60 from the minutes and add 1 to the hours.

1 :75

+1 - :60

2 :15 p.m.

Daniel arrived at the apartment at 2:15 p.m.

8 0

3 years ago

Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12

BARSIC [14]

We are told that Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper.

Since we know that range of a data is difference between the highest and lowest values of a data set. Range of our data set will be 4 (14-10). A group of different ages could have same range as Christina's data set. So range will be not a good option.

A measure of central tendencies will be better option to represent information about ages of softball team players. Mean will give the average age of softball players.

$\text{Mean age of players}=\frac{10+11+11+12+12+12+12+12+13+13+13+14}{12}$