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miv72 [106K]
3 years ago
6

Sodium bicarbonate (NaHCO3) is commercially known as baking soda. How many grams and atoms of oxygen are there in 15 grams of so

dium bicarbonate? The molar mass of NaHCO3 is
84.01 g/mol.​
Chemistry
1 answer:
ella [17]3 years ago
4 0

Answer:

3 atoms of O

8.57g

Explanation:

The problem here is to find the mass of oxygen in the compound and the number of atoms of oxygen.

 The formula of the compound is:

 NaHCO₃;

   Here we have:

      1 atom of Na

     1 atom of H

     1 atom of C

     3 atoms of O

So there are 3 atoms of O

To find the mass of oxygen , we use the molar mass of oxygen;

     Molar mass of oxygen  = 16g/mol

 Mass of oxygen  = \frac{3(16)}{84.01}  x 15  = 8.57g

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Read 2 more answers
Oxygen gas, generated by the reaction 2 KClO 3 ---- 2 KCl + 3 O 2 , is collected over water at 27 C in a 2.00 L vessel at a tota
laila [671]

Answer:

The moles of KClO3 = 0.052 moles

Explanation:

Step 1: Calculate the pressure of oxygen gas

The oxygen has a total pressure (including water vapour) of 760 mmHg

The pressure of Oxygen = (760 - 26) mmHg

                                         = 734 mmHg of water vapor

Step 2: Calculate the no of moles of oxygen

        Using Ideal gas equation

        P V = n R T

       P = pressure of oxygen in N/m2 ( you should convert 734 mmHg to pascal or N/m2) = 97,858.6 N/m2 or pas

       V = 2 litres = 0.002 m3

       R = gas constant = 8.31

       T= 27oC = 300 K

Applying this equation P V = n R T

        97,858.6 x 0.002 = n x 8.31 x 300

        n = 0.0785 mol of Oxygen

From the balanced equation

2 KClO 3 ---- 2 KCl + 3 O 2

3 moles of oxygen is produced from 2 moles KClO3

so 0.0785 mole of oxygen will be produced from x

x = (0.0785 x 2 ) / 3

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