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sweet [91]
3 years ago
9

5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure water.

Chemistry
1 answer:
Rudik [331]3 years ago
7 0

Answer:

2.8 m

Explanation:

Step 1: Given data

  • Moles of potassium bromide (solute): 0.210 mol
  • Mass of water (solvent): 0.075 kg

Step 2: Calculate the molality of the solution

Molality is a unit used to express the concentration of a solution. It is equal to the moles of solute divided by the kilograms of solvent.

m = moles of solute / kilograms of solvent

m = 0.210 mol / 0.075 kg

m = 2.8 mol/kg = 2.8 m

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4 0
4 years ago
Xas shown in table 15.2, kp for the equilibrium n21g2 + 3 h21g2 δ 2 nh31g2 is 4.51 * 10-5 at 450 °c. for each of the mixtures li
Agata [3.3K]
According to the balanced equation of this reaction:
N2(g) + 3H2(g) ↔ 2NH3(g)
and when we have Kp = 4.51 x 10^-5 so, in the Kp equation we will substitute by the value of the P for each gas to compare the value with Kp = 4.51x10^-5

a) when we have 98 atm NH3, 45 atm N2, 55 atm H2 by substitution in Kp equation:
Kp= [p(NH3)]^2 / [p(N2)]*[p(H2)]^3 = [98]^2 / [45]*[55]^3
                                                        = 1.28x10^-3 
So here the value is higher than the value of the given Kp.
so the reaction will go leftwards toward the reactants ( to reduce the value of Kp) to reach the equilibrium. 
b) When 57 atm NH3, 143 atm N2, No H2 so like a) by substitution:
Kp = [57]^2 / [143] = 22.7
So the reaction will go leftwards toward the reactants to reduce the value of Kp to reach equilibrium.
c) when 13 atm NH3, 27 atm N2, 82 H2
Kp = [13]^2 / [27]*[82]^3 = 1.135 x 10^-5 So this value is lower than the Kp which is given.
 so, the reaction will go towards the right toward the products to increase the value of Kp to reach the equilibrium.  
8 0
3 years ago
What is the mass percent of each element in water
Vladimir79 [104]

Mass Percent of Hydrogen. To find the mass percent of hydrogen in water, take the molar mass of hydrogen in the water molecule, divide by the total molar mass of water, and multiply by 100. Dividing 2.016 by 18.016 gives you 0.1119. Multiply 0.1119 by 100 to get the answer: 11.19 percent

5 0
4 years ago
In salt, what is the nature of the bond between sodium and chlorine? in salt, what is the nature of the bond between sodium and
kifflom [539]

A chemical bond that involves the transfer of electrons from a metal to a nonmetal and thus forms ions and the atoms in the molecule are attracted towards each other through electrostatic force of attraction are said be ionic bond. In short, the bond formed between the two oppositely charged ions.

In salt, the compound formed between sodium and chlorine is sodium chloride having molecular formula NaCl where sodium is a metal and chlorine is the non-metal. The formation of the compound takes place by transfer of an electron from sodium thus forming a cation of formula Na^{+} to chlorine which gains electron and thus results in an anion formation having formula Cl^{-}. The force of attraction between these oppositely charged ions that helds them together and results in formation of NaCl compound is electrostatic force of attraction.

Hence in salt, the nature of bond between sodium and chlorine is ionic.

4 0
4 years ago
Una masa de aire ocupa un volumen de5litro a una temperatura de 120c Cual será el nuevo volumen si la temperatura se reduce ala
zalisa [80]

Answer:

1. V_2=2.5L

2. V_2=8000mL

3. V_2=176.3L

Explanation:

¡Hola!

En este caso, dada la información para estos problemas, procedemos de la siguiente manera, basado en las leyes de los gases ideales:

1. Una masa de aire ocupa un volumen de 5 litros a una temperatura de 120 °C Cual será el nuevo volumen si la temperatura se reduce a la mitad:

Aqui, utilizamos la ley de Charles, asegurándonos que la temperatura está en Kelvin:

\frac{T_2}{V_2} =\frac{T_1}{V_1} \\\\V_2 =\frac{V_1T_2}{T_1} \\\\V_2 =\frac{5L*196.5K}{393K} \\\\V_2=2.5L

2. Un gas ideal ocupa un volumen de 4000 ml a una presión absoluta de 1500 kilo pascal Cual será la presión si el gas es comprimido lentamente hasta 750 kilo pascal a temperatura constante?

Aquí, utilizamos la ley de Boyle, dado que la temperatura se mantiene constante, calculando el volumen, ya que lo que se da es la presión final:

\neq P_2V_2=P_1V_1\\\\V_2=\frac{P_1V_1}{P_2}\\\\ V_2=\frac{4000mL*1500kPa}{750kPa}\\\\V_2=8000mL

3. Un gas ocupa un volumen de 200 litros a 95°C y 782 mmHg Cual será el volumen ocupado por dicho gas a 65°C y 815 mmHg:

Aquí, utilizamos la ley combinada de los gases ideales, asegurándonos que las temperaturas están en Kelvin:

\frac{T_2}{P_2V_2} =\frac{T_1}{P_1V_1} \\\\V_2 =\frac{P_1V_1T_2}{P_2T_1} \\\\V_2 =\frac{782mmHg*200L*338K}{815mmHg*368K}\\\\V_2=176.3L

¡Saludos!

6 0
3 years ago
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