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3 years ago

What is the factors for x squared plus 5x - 6

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

6 0

Answer:

(x+6)(x-1)

Step-by-step explanation:

x^2+6x-x-6

x(x+6)-(x+6)

(x+6)(x-1)

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Michael is a real estate agent who sells a house. He received $5,250 for a 3% commission on the house. How much did the house se

Alborosie

Answer: $157.50

Step-by-step explanation:

$5250÷100=$52.50

52.50×3=$157.50

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3 years ago

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Austin is building a miniature replica of the empire state building. the actual empire state building is 1,423 feet tall and 6,0

Fofino [41]

60/6000 = x/1423

100/1 = 1423/x

100x = 1423

x = 14.23 --> About 14 cm

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3 years ago

Factor -28x2-12x , thank you all for helping me answer these questions.

goldenfox [79]

<span>-28x²-12x = -4x(7x+3) the first one is answer</span>

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3 years ago

Which relation is a function?

NISA [10]

Answer:

1. yes

2. yes

3. no

4. no

5. yes

Step-by-step explanation:

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3 years ago

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How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago