20,25 and 35,50 and 10,15. Each pair would have a GCF of 5.
Answer:
A) The legs are 9 & 12 inches.
B) The hypotenuse is 15 inches.
<em>Hope that helps! :) <3</em>
Step-by-step explanation:
Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Given:
A figure of a triangular prism.
Height of triangular base = 
yd
Base of triangular base = 4 yd
Height of prism = 4 yd.
To find:
The volume of the triangular prism.
Solution:
Volume of a triangular prism is:
...(i)
Where, B is the area of triangular base and h is the height of the prism.
Area of triangular base is:
Putting and h=4 in (i), we get
The volume of the triangular prism is 77.3 cubic yards. Therefore, the correct option is 2.
Answer:
the correct points would be one unit to the right, thusly, (2,4) (4,-1) (-2,1)
Step-by-step explanation:
