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2 years ago

Please answer this correctly

Mathematics

1 answer:

erastovalidia [21]2 years ago

8 0

The right answer is 40 cm

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

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Sarah has 13 stickers. Sissy has 28 stickers. Sissy divides her stickers into 4 equal groups.

777dan777 [17]

Answer:

She gave 7 stickers.13+7=20.sarah has 20 stickers

Step-by-step explanation:

Divide 28 by 4

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1 year ago

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

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1 year ago

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Marianna [84]

Answer:

32.8937 units

Step-by-step explanation:

So, we can imagine this as a right triangle with a length of 11 (THe change of the X's) and the height being 31 (Change of the Y's)

Then we use pythagorean therom to find the hypotenuse (the length)

11^2 + 31^2 = c^2

121+961 = C^2

1082 = c^2

32.8937units

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1 year ago