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ArbitrLikvidat [17]
3 years ago
9

1) 2m + 3m2 - 4m

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

1) 2m + 3m2 - 4m=7

7) 3m2 – 2m + 4m= 11

8) 20 + 109 + 39 - 4= 164

3) 2m + 4m - 3m2= -3

9) 4xy + x + 2xy= 0

4) 2y + 14x - 7x + 9y= 18

10) 6m2 - 6m - 9m2= -51

Step-by-step explanation:

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3 years ago
The price of a dress is reduced by 60%.When the dress still does not​ sell, it is reduced by 60% of the reduced price. If the pr
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Answer:

1. $450

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Step-by-step explanation:

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3 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
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