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3 years ago

1) 2m + 3m2 - 4m

Mathematics

1 answer:

Lilit [14]3 years ago

5 0

Answer:

1) 2m + 3m2 - 4m=7

7) 3m2 – 2m + 4m= 11

8) 20 + 109 + 39 - 4= 164

3) 2m + 4m - 3m2= -3

9) 4xy + x + 2xy= 0

4) 2y + 14x - 7x + 9y= 18

10) 6m2 - 6m - 9m2= -51

Step-by-step explanation:

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What is the value of g?<br> g<br> 70

lara [203]

Answer: 70

Step-by-step explanation:

easy

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3 years ago

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blagie [28]

I believe the answer should be 4 and 2

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3 years ago

Perpendicular lines AB and CD intersect at point E. If m2AED = x+ 20, what is the value of

Leona [35]

Answer:

x = 70

Step-by-step explanation:

Since the lines are perpendicular then ∠ AED = 90°, thus

x + 20 = 90 ( subtract 20 from both sides )

x = 70

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3 years ago

Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi

Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

$\dfrac{f(b)-f(a)}{b-a}$

compute the quantity

$\dfrac{f(3)-f(0)}{3}$

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

$\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3$

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

$\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}$

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

$h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6$

And so the average rate of change is

$\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4$

3 0

4 years ago

Simplify square root of 2 over cube root of 2.

Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

$\sqrt[n]{x} = {x}^{ \frac{1}{n} }$

So you can rewrite the given fraction as

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }$

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } } = {2}^{ \frac{1}{2} - \frac{1}{3} }$

Since

$\frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6}$

the answer is

${2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}$

3 0

3 years ago

Read 2 more answers