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Alex17521 [72]
4 years ago
10

Help me !!!!!!! Please!!!!

Mathematics
1 answer:
Alina [70]4 years ago
4 0
The correct answer is C.

Hope this helps
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Malik’s solution to the equation 2/5x-4y=60 is shown below
frozen [14]

Answer:a

Step-by-step explanation:

5 0
3 years ago
Gene's frying pan is 13.5 inches in diameter. What is the circumference of his frying pan?
STALIN [3.7K]
To work out the circumference of a circle, you should use 2πr or πd (r being radius and d being diameter)
So 
Circumference = 13.5 x π = 27/2 π = 42.41 inches
5 0
3 years ago
Find the mean of each of these set of numbers <br> a. 5,3,4,8 b. 7,5,6,5,7 c. 15,12,10,12,11
Svetllana [295]
The correct answers are
A) 5
B) 6
C) 12
6 0
3 years ago
Is 6 /1.2 a rational number
olasank [31]

Answer:

yes

Step-by-step explanation:

A rational number can be expressed in the form

\frac{a}{b} ← where a, b are integers

Given

\frac{6}{1.2} ← multiply numerator/ denominator by 10

= \frac{60}{12} = 5 = \frac{5}{1} ← a rational number

5 0
3 years ago
How do you interpret the estimated value of coefficient of EDU in the following equation:
tia_tia [17]

Answer:

The correct option is d

Step-by-step explanation:

From the question we are told that

The equation is ln  (SALARY) =  1 + 0.02 ln(EDU)

generally

ln (e) =  1

=> ln  (SALARY) =  ln (e) + 0.02 ln(EDU)

Apply log rules

=> ln (SALARY) = ln[ e(EDU)^{0.02} ]

=> SALARY  =  e(EDU)^{0.02}

When EDU is increase by 1% we have that

\frac{1}{100}  *  EDU  + EDU

=> 1.01 EDU

So the new SALARY will now be

SALARY''  =  e(1.01EDU)^{0.02}

The ratio by which the new SALARY will increase is obtain by dividing the value of new SALARY (SALARY'' ) with that of the former SALARY (SALARY) and this mathematically represented as

\frac{SALARY'' }{SALARY}  =  \frac{e*1.01 (EDU)^{0.02}}{e (EDU)^{0.02}}

=> \frac{SALARY ''}{SALARY} =  1.0002

Generally the percentage increase of salary is mathematically evaluated as

k=  (\frac{SALARY''}{SALARY}  - 1 ) *  100

=> k=  (1.0002 - 1 ) *  100

=> k=  0.02 \%

5 0
4 years ago
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