Describe how to determine the solution of a system of two linear equations by graphing.

2 answers:

7 0

1). Draw the graph of one equation.

2). On the same graph, draw the graph of the other equation.

3). If the two lines cross, the x and y at the point where they cross are the solution to the system of two equations.

4). If the two lines don't cross, then the system has no solution.

5). If they are the same line, then the two equations are the same equation, and every point on the line is a solution to it.

levacccp [35]3 years ago

4 0

Using the graphing you graph the two equations and then find the point where the two lines of the equation meet.

Hope this helps :)

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Select the correct answer from each drop down menu y=x^2+2x-1 y-3x=5

tatiyna

The drop down menus are not provided. However, I will help get the solution of the system of equation which is the requirement of the question.

Answer:
(3,14) and (-2,-1) are the solutions of the system

Explanation:
The first equation given is:
y = x² + 2x - 1 .........> equation I
The second given equation is:
y - 3x = 5
This can be rewritten as:
y = 3x + 5 ..........> equation II

Equate equations I and II and solve for x as follows:
x² + 2x - 1 = 3x + 5
x² + 2x - 1 - 3x - 5 = 0
x² - x - 6 = 0
(x-3)(x+2) = 0

either x-3 = 0 .........> x = 3
or x+2 = 0 ...........> x = -2

Now, we get the values of y by substituting in equation II as follows:
At x = 3:
y = 3x + 5
y = 3(3) + 5
y = 14
The first solution is (3,14)

At x = -2:
y = 3x + 5
y = 3(-2) + 5
y = -1
The second solution is (-2,-1)

Hope this helps :)

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