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emmainna [20.7K]

2 years ago

6

The first day of the snowstorm, there were 9.2 centimeters of snow. During the second day of the storm, another 18.2 centimeters

fell. If the total snowfall for the three-day snowstorm was 39.1 centimeters, how much snow fell on the third day?

1 answer:

maria [59]2 years ago

6 0

Answer:

11.7

Step-by-step explanation:

39.1 - 9.2 = 29.9

29.9 - 18.2 = 11.7

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The bus fare in a city is $2.00. People who use the bus have the option of purchasing a monthly coupon book for $28.00. With the

LekaFEV [45]

Answer:

56 = 56

Step-by-step explanation:

Given:

Bus fare = $2.00

coupon book = 28.00

bus fare w/ coupon book = $1.00

let x be the number of bus rides.

2.00x = 1.00x + 28.00

2.00x - 1.00x = 28.00

1x = 28.00

x = 28.00

24 bus rides for both to have the same cost.

2.00x = 1.00x + 28

2.00(28) = 1.00(28) + 28

56 = 28 + 28

56 = 56

4 0

2 years ago

Can you please help me please please help

Triss [41]

Answer:

there is the answers❤ sorry its a little blurry

4 0

2 years ago

Help me pleaseeee asap

sdas [7]

Answer:

5089.4cm³ (rounded to 1 d.p.)

Step-by-step explanation:

Volume of cylinder = $\pi$ × r² × h

Volume of cylinder = $\pi$ × 9² × 20

= 1620 $\pi$

= 5089.4cm³ (rounded to 1 d.p.)

4 0

2 years ago

Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac

agasfer [191]

Answer:

a) $\frac{8}{9}$ =0.89

b) 0.8413

Step-by-step explanation:

we know that

$P(║ x -\mu║ \leq k\sigma) \geq 1 -\frac{1}{k^2}$

$so, \mu = 150, \sigma = 20$

$k = \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3$

$P(║ x -150 ║ \leq 3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}$

x - N(150, 20^2)

$P(X \leq 170) = 0.8413447$

check

$P norm = \frac{170 - 150}{20}= 0.8413447$

8 0

3 years ago

Given g(x) = 2(x – 5), determine x for g(x) = -30.

GREYUIT [131]

When g(x) = -30, x = -10
To solve, make -30 equal to 2(x-5):
-30 = 2(x-5)
-30 = 2x -10
-20 = 2x
-10 = x

5 0

2 years ago