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Lubov Fominskaja [6]
3 years ago
7

PLS ANSWER THE QUESTION QUICK

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0
3x+5=-2x-10


solution:

x=3
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The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
If you see that gasoline costs $1.70 in Georgia and $3.40 in California, you can
grin007 [14]

The question is incomplete:

If you see that gasoline costs $1.70 in Georgia and $3.40 in California, you can  conclude that gasoline is twice as expensive in California as in Georgia. This  conclusion from this comparison reflects the function of money as a:

-store of value

-an object with a value that varies sharply from one place to another

-medium of exchange

-unit of account

Answer:

Unit of account

Step-by-step explanation:

-Store of value refers to something that can be kept for a period of time and maintains its value in the future.

-An object with a value that varies sharply from one place to another  means that products can have different prices in different places.

-Medium of exchange refers to an object with an standard value that allows  you to purchase goods or services.

-Unit of account refers to a numerical unit that allows you to compare the value of products and services.

According to this, the answer is that this  conclusion from this comparison reflects the function of money as a unit of account because it indicates that money works as a unit that you can use to compare the value of products, in this case the price of gasoline in different places.

6 0
2 years ago
Anyone ? what’s the volume of the cylinder
katen-ka-za [31]

Answer:

V=πr2h

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
Use the "mixed partials" check to see if the following differential equation is exact. If it is exact find a function F(x,y) who
Arturiano [62]

We have

(-3xy^2+y)_y=--6xy+1

and

(-3x^2y+x)_x=-6xy+1

so the equation is indeed exact. So we want to find a function F(x,y)=C such that

F_x=-3xy^2+y

F_y=-3x^2y+x

Integrating both sides of the first equation wrt x gives

F(x,y)=-\dfrac32x^2y^2+xy+f(y)

Differentiating both sides wrt y gives

F_y=-3x^2y+x=-3x^2y+x+f_y\implies f_y=0\implies f(y)=C

So we have

F(x,y)=-\dfrac32x^2y^2+xy+C=C

or

F(x,y)=\boxed{-\dfrac32x^2y^2+xy=C}

3 0
3 years ago
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