The integers are 29 and 30.
Sqrt (53) = 10 * sqrt (0.53)
0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27
sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4
sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33
Answer:
1. $58650
Step-by-step explanation:
Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
I hope you enjoyed my explanation. :)
We are given a figure where M, N , O and P points are given.
We need to explain if points O, N, and P collinear or not.
Note: All co-linear points are in a straight line.
From the figure, we can see that <em>O and N points are in a straight line but point P is aside.</em>
So, the points O, N, and P are not collinear.
Therefore, correct option is "<u>No, the three points are not collinear</u>".
