The applicable theorem is the one that tells you the exterior angle is equal to the sum of the opposite interior angles.
9x = (5x) +(9 +x)
9x = 6x +9 . . . . . . . . collect terms
3x = 9 . . . . . . . . . . . . subtract 6x
x = 3 . . . . . . . . . . . . . divide by 3
The value of x is 3.
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The angles (clockwise from left) are then
(9*3)° = 27°
(5*3)° = 15°
(9 +3)° = 12°
This is an obtuse triangle, obviously not drawn to scale.
Since vertical angles are equal you can put the same value to the opposite angles. Also, you were given a supplementary angle which are two angles added to 180 degrees. Of those 180 you were given 100. The angle next to the 100 degrees has a value of 80. With all this, you add all the angles together and put it equal to 180 which is what the angles of a triangle add up to. Then you combine like terms to get the value of X and just replace it for x. After that you just multiply and then add.
Nothing is bigger than 5/6 and smaller than 3/8 because 5/6 is already larger than 3/8.
Start out by finding the area of the square.
a = 4²
a = 16
Since all we have to look at is 1/4 of this square, multiply the area by 1/4.
(16)1/4
4
The area of the triangle is 4.
Now we need the area of the circle.
a = πr²
Sub: a = π(2)²
a = π(4)
Since the portion of the circle that covers the triangle is 1/4 of the circle, subtract 1/4 of the area of the circle from the area of the circle.
a = 4 - 1/4(π(4))
a = 4 - 1/4π x 1
a = 4 - 1/4π
Now this is where it's supposed to go, considering the fact that π isn't given a value.
Normally, I'd use 3.14 for π, as the entire population would, and then it would be easy, but obviously that isn't an option.
Now this answer isn't up there, so my best option is to tell you it's most likely c, and I hope I'm right.
Uhh good luck I guess this math test is weird
-Xax