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olga_2 [115]
2 years ago
10

Joshua invested $750 in an account paying an interest rate of 3\tfrac{1}{4}3 4 1 ​ % compounded quarterly. Josiah invested $750

in an account paying an interest rate of 2\tfrac{5}{8}2 8 5 ​ % compounded annually. After 18 years, how much more money would Joshua have in his account than Josiah, to the nearest dollar?
Mathematics
1 answer:
Nat2105 [25]2 years ago
4 0

Answer:

Due to the difference in the interest rate and the quarterly compounding, Joshua will have $212.24 more than Josiah.

Step-by-step explanation:

Giving the following information:

Joshua:

Initial investment (PV)= $750

Interest rate (i)= 0.0341/4= 0.008525

Number of periods (n)= 18*4= 72 quarters

Josiah:

Initial investment (PV)= $750

Interest rate (i)= 0.0285

Number of periods (n)= 18 years

<u>To calculate the future value of each one, we need to use the following formula:</u>

FV= PV*(1 + i)^n

Joshua:

FV= 750*(1.008525^72)

FV= $1,381.98

Josiah:

FV= 750*(1.0285^18)

FV= $1,169.74

Due to the difference in the interest rate and the quarterly compounding, Joshua will have $212.24 more than Josiah.

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jack has 14 cards. by the end of the week his amount of cards has doubled. how many cards does jack have now
slava [35]

Answer:

Jack has 28 cards.

Step-by-step explanation:

To double 14, multiply 14 times 2. 14x2=28

6 0
3 years ago
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Is the bisector of ∠ABC and is the bisector of ∠ACB.
ycow [4]

Answer:

ASA

Step-by-step explanation:

You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.

7 0
3 years ago
Roxanne graphed this system of equations to find the solution.
Mice21 [21]

Answer:

Option C is correct.

She is not correct as she use the wrong y intercepts when graphing the equations.

Step-by-step explanation:

Given the system of equations:

y = \frac{2}{3}x-5         .....[1]

y = -2x+3         .           .....[2]

equate these two equations we get;

\frac{2}{3}x-5=-2x+3

Add 5 to both sides we get;

\frac{2}{3}x = -2x+8

Add 2x to both sides we have;

\frac{8}{3}x = 8

Multiply both sides by 3 we get;

8x = 24

Divide both sides by 8 we get;

x = 3

Substitute the value of x in [2] we have;

y = -2(3)+3 = -6+3

Simplify:

y = -3

Therefore, the correct solution for this given system of equation is (3, -3)

You can see the graph of these equations below.

5 0
2 years ago
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Can someone pls answer this?❤️
nata0808 [166]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)
lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

y + 3 = \frac{1}{2}(x-6)

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or y-y_1 = m (x-x_1) format. Remember that the number in place of the m is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction (-\frac{2}{1}), and flip its numerators and denominators. Therefore, the perpendicular slope would be \frac{1}{2}.

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, y-y_1 = m (x-x_1). In order to write an equation, the x_1, y_1, and m have to be substitute for with real values.

The m represents the slope. We already calculated that in the last step, so put \frac{1}{2} in place of the m. The x_1 and y_1 represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for x_1 and -3 for y_1:

y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)

Therefore, (again, assuming that the line can be put in point-slope form) the answer is y + 3 = \frac{1}{2}(x-6).

5 0
3 years ago
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