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3 years ago

Which set best represents the positive integers?

Mathematics

1 answer:

alexira [117]3 years ago

8 0

Answer:

O A. {1,2,3,4,...)

Step-by-step explanation:

Its not B because it holds 0 which is ±

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Help plz. 3:5=____%

NemiM [27]

Answer:

3:5=_____%

Step-by-step explanation:

3:5 equal to 60%

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3 years ago

24 students in a class took an algebra test If 18 students passed what percent passed

Anuta_ua [19.1K]

Answer: 75%

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3 years ago

David has $100.00 saved in the bank. a payment is taken out of his account for $150.00. he makes a deposit for $50.00 but at the

Dmitry_Shevchenko [17]

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4 years ago

Read 2 more answers

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

4 years ago

Katherine and Crystal do landscaping. They recently earned $1472 for a project. If Katherine earned $5 for every $3 earned by Cr

Degger [83]

Answer:

Katherine: 920

Crystal: 552

Step-by-step explanation:

The total amount earned by each is 1472

The ratio of the earnings is Katherine / Crustal = 5/3

The total number of shares = 5 + 3 = 8

So the proportion for Katherine

5/8 = x / 1472 Cross multiply

8x = 5 * 1472

8x = 7360

x = 7360/8

x = 920

And the proportion for Crystal is

3/8 = x / 1472 Cross multiply

8x = 3 * 1472

8x = 4416

x = 4416 / 8

x = 552

4 0

3 years ago