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2 years ago

5

Marisol scored 80% on her math test. The test had 45 questions, and each question was worth the same amount of the final score.

How many questions did Marisol answer correctly?

1 answer:

vampirchik [111]2 years ago

6 0

Answer:

She answered 36 questions correctly out of the 45 questions.

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Which is the correct classification of sqrt 32

labwork [276]

Answer:

irrational number, nonrepeating decimal

Step-by-step explanation:

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3 years ago

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What are the coordinates of point P? Please help show steps it’s urgent!

Vlad [161]

Answer:

A (2, -8/5)

Step-by-step explanation:

The answer would be A I believe. This is because to get from C to D, it would be going down 6 and to the right by 10.

To make CP = 3/5CD. We multiply how much we move by 3/5:

-6 * 3/5 = -18/5 (note that the 6 would be negative because its going down)

and 10 * 3/5 = 6

Then we add these values to the coordinates of C:

(-4 + 6, 2 - 18/5) =

(2, -8/5). So A would be the answer.

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3 years ago

3 times a number plus 5 is breathers than 12. Graph the possible solutions

Korolek [52]

3x12+5 is greater than 12 .

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2 years ago

How many 1/3 cups servings are in 4 cups

Andrew [12]

Only one that would make sense is 1/12

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2 years ago

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In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

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2 years ago