2 and 4/7, 32/14, 9/3.5, Ect.
Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
the answer is 39 because you need to divide.
8/15 x 5/6
•multiply across the numerator and denominator.
= 40/90
• then find a common factor that will go into both the numerator and denominator equally.
Common factor: 5
= 8/18
•there is another common factor, which is 2
Simplified:
=4/9
Answer:
y = 2x - 3
Step-by-step explanation:
Parallel lines have the same slope
only the constant changes
y = 2x + b
To find "b"
Plug in point (3, 3)
3 = 2(3) + b
3 = 6 + b
Subtract 6 from both sides
-3 = b
The equation for the parallel line is
y = 2x - 3