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Brums [2.3K]
3 years ago
7

PLEASE GRAPH THIS AND SHOW THE Y AND X INTERCEPT​

Mathematics
1 answer:
Reil [10]3 years ago
3 0

Answer:

I found this : graph the inequality by finding the boundry line, then shading the appropriate area

8 > 10p^2h-8c/5   (draw a line under the >)

Step-by-step explanation:

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Vince's birthday party is going to be at his favorite science museum next weekend. He has 8 friends who want to see the Dinosaur
Sunny_sXe [5.5K]

Answer:

See explanation

Step-by-step explanation:

Dinosaur Discovery show = 8 friends

Wild Weather show = 4 friends

Cost of Dinosaur Discovery show = $d

Cost of Wild Weather show = $w

At regular price:

Total cost of his friends' tickets = 8 * d + 4 * w

= 8d + 4w

At half price

Total cost of his friends' tickets =

8 * 1/2d + 4 * 1/2w

= 8/2d + 4/2w

= 4d + 2w

Total cost of his friends' tickets = 4d + 2w

6 0
3 years ago
Is there some one who can help me please
lesya692 [45]

Answer:

I'd say $18

Step-by-step explanation:

I cant really tell, but your best guess is $18

6 0
3 years ago
Please help me !!!!!!!!
astraxan [27]
It's C the missing side is 9 units long so since cosine is adjacent divided by hypotenuse it would be 9/41
5 0
3 years ago
Read 2 more answers
What’s the difference quotient simplified
mihalych1998 [28]

\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}

7 0
3 years ago
Tom's weight = 500 pounds
ruslelena [56]

Answer:

88% of his weight remains

5 0
3 years ago
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