Question

2x - y - 4 = 0

Answer 1

Hello :
2x - y - 4 = 0 ....(1)
3x + y - 9 = 0 ....(2)
(1)+(2) : 5x-13 =0
5x=13
x=13/5
subsct in (2) :3(13/5)+y-9=0
y = 9-39/5
y=6/5
answer : b. {(13/5, 6/5)}

Answer 2

Answer:

Option B.

Step-by-step explanation:

The given equations of the system are

2x - y - 4 = 0

2x - 4 = y ------(1)

3x + y - 9 = 0

3x + y = 9

y = 9 - 3x ------(2)

By replacing the value of y from equation (1) to equation (2)

2x - 4 = 9 - 3x

2x = 4 + 9 - 3x

2x = 13 - 3x

2x + 3x = 13

5x = 13

x = $\frac{13}{5}$

Now we plug in the value of x in the equation (1)

$y=9-(3\times \frac{13}{5})$

$y=9-(\frac{39}{5})$

$y=\frac{45-39}{5}$

$y=\frac{6}{5}$

Therefore, solution of the given system is $[\frac{13}{5},\frac{6}{5}]$.

Option B. is the answer.