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Katen [24]
3 years ago
9

three consecutive terms in a geometric sequence are r ,r+4, and r+6 in that order. Determine the value of r.​

Mathematics
2 answers:
Semmy [17]3 years ago
7 0

9514 1404 393

Answer:

  r = -8

Step-by-step explanation:

The terms of a geometric sequence have a common ratio, so we have ...

  \dfrac{r+4}{r}=\dfrac{r+6}{r+4}\\\\1+\dfrac{4}{r}=1+\dfrac{2}{r+4}\\\\4(r+4)=2(r)\qquad\text{subtract 1, cross multiply}\\\\2r=-16\qquad\text{subtract $2r+16$}\\\\\boxed{r=-8}\qquad\text{divide by $2$}

_____

Then the terms of the sequence are ...

  -8, -4, -2, ...

and the common ratio is 1/2.

maxonik [38]3 years ago
3 0

Answer: r = -8

Step-by-step explanation:

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