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3 years ago

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How many solutions does each polynomial have?

2 answers:

maria [59]3 years ago

7 0

Answer:

answer in picture

Step-by-step explanation:

Ivenika [448]3 years ago

5 0

1) Y=6x-9 set y to 0 so 0=6x-9. You would get x=-3/2 so that is ONE SOLUTION

2) 0 solution

3) 0 solution

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Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

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2 years ago

Pedro is saving part of his allowance to buy a gift for his teacher. At the end of 10 weeks he has saved $95.50 . Pedro saved th

aev [14]

Answer:

Pedro saves $9.55 each week.

4 0

3 years ago

Given f(x), match each expression to its correct value

Murljashka [212]

Answer:

-11, f(-5) 1

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the sum of the interior angle measures of the polygon

pshichka [43]

<h3>Answer: 1260</h3>

Work Shown:

We have 9 sides of this polygon. See the diagram below. So n = 9

Plug that into the formula below to find the sum of the interior angles

S = 180(n-2)

S = 180(9-2)

S = 180*7

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2 years ago

(x+7)(x-9)<br><br> Multiply Ponomials <br><br> show work please

Murrr4er [49]

Answer:

x(x-9)+7(x-9)

x²-9x+7x-63

x²-2x-63

7 0

3 years ago