Answer:
johnsons rule minimizes total idle time for both machines or work centers. What technique is used when setup times at a workstation are sequence dependent? determine the total time of each job sequence permutation considering the setup time and choose the best (lowest) time.
Explanation:
please mark me as brainliest thank you
Answer:
The correct option is;
Selecting the correct browser to use for the sites you want to visit
Explanation:
Censorship of information is the subduing of information based on the consideration of such information being harmful or inconvenient
Increased anonymity
Making an individual anonymous which is one of the capabilities of the internet, is seen as encouraging unethical behavior and promoting discussions which are deemed uncivil in a commonly shared space online.
Unauthorized sharing of copyrighted information
The sharing and distribution of copyrighted material is against the law but it is a common occurrence and in various formats online
Out of the given options, selecting the correct browser to use for the sites you want to visit is the one that is not a concern.
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}
When was the Ming dynasty established?
the 1100s CE
the 1200s CE
the 1300s CE
the 1400s CE
There are two standard colors for a text in a them