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3 years ago

2/11 rounded to the nearest thousand

Mathematics

1 answer:

trasher [3.6K]3 years ago

6 0

Answer:

Step-by-step explanation:

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If 1/2 of 5 is 3, then what is 1/3 of 10?

Dahasolnce [82]

3.3 repeated hope this helps

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3 years ago

If a snowball melts so that its surface area decreases at a rate of 3 cm2/min, find the rate (in cm/min) at which the diameter d

grin007 [14]

Answer:

The diameter decreases at a rate of 0.053 cm/min.

Step-by-step explanation:

Surface area of an snowball

The surface area of an snowball has the following equation:

$S_{a} = \pi d^2$

In which d is the diameter.

Implicit differentiation:

To solve this question, we differentiate the equation for the surface area implictly, in function of t. So

$\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}$

Surface area decreases at a rate of 3 cm2/min

This means that $\frac{dS_{a}}{dt} = -3$

Tind the rate (in cm/min) at which the diameter decreases when the diameter is 9 cm.

This is $\frac{dd}{dt}$ when $d = 9$ . So

$\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}$

$-3 = 2*9\pi\frac{dd}{dt}$

$\frac{dd}{dt} = -\frac{3}{18\pi}$

$\frac{dd}{dt} = -0.053$

The diameter decreases at a rate of 0.053 cm/min.

7 0

3 years ago

What is the area of a trapezoid ABCD with bases AB and CD

Delvig [45]

A= a+b/2h =10+20/2 x13 =195

I believe 195 is correct if not, I’m so sorry

3 0

3 years ago

Read 2 more answers

Math question up here

Gemiola [76]

The answer is 11 because you do the smallest parenthesis. and work your way out.

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3 years ago

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Factor: 64v^4 - 225w^10

love history [14]

Answer:

( $8v^2-15w^5)(8v^2+15w^5)$

Step-by-step explanation:

STEP 1:

$8^{2}$ $v^{2*2}$ - $15^{2}$ $w^{2*5}$

STEP 2:

$8^{2}$ * $(v^{2})^{2}$ - $15^{2} * (w^{5})^{2}$

STEP 3:

$(8v^2)^2 - (15w^5)^2$

STEP 4:

( $8v^2-15w^5)(8v^2+15w^5)$

6 0

3 years ago