Answer:
A. $6.67
Step-by-step explanation:
a) 2y -3x + 8
a) y = - 3/2x + 8/2
a) y = - 3/2x + 4
b) 5y - 15x = -30
b) 5y = 15x - 30
b) y = 15/5x - 30/5
b) y = 3x - 6
3x - 6 = 3/2x + 4
3x -3/2x = 4+6
3/2x = 10
x = (10) / (3/2) = $6.67
1/2,3/4,2/3...................
Answer:
The correct answer is 5 years i.e. 2008.
Step-by-step explanation:
Price of the automobile in 2003 is $32000.
Depreciation per year is given by $1740.
Therefore let the car value is depreciated for t number of years.
Value depreciated for t years is given by $ (1740t).
The final value of the car after t years is given to be $23300.
Thus the equation is given by 32000 - 1740t = 23300.
⇒ 1740t = 32000 - 23300
⇒ 1740t = 8700
⇒ t = 5
Thus after 5 years the value of the car is $23300.
Thus in 2008 the depreciated price of the car would be $23300.
