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3 years ago

10

A student claims that the inequality 4x + 6 > 0 always true because all real numbers multiplied by 4 plus 6 will be greater t

han 0. Explain the student's error.

1 answer:

ehidna [41]3 years ago

8 0

Step-by-step explanation:

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At 1 P.M., the total snowfall is 5 centimeters. At 4 P.M., the total snowfall is 16 centimeters. What is the mean hourly snowfal

Yuri [45]

Answer:

Mr. Snowbully

Step-by-step explanation:

I think the mean hourly snowfall is named Mr. Snowbully

It's a funny name!

Well, the snow would grow at a rate of 4 cm every hour so...

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3 years ago

The resistance, R of a wire varies directly as the length, l, and inversely as the diameter, d, squared. If R is 1.50ohms when l

tatyana61 [14]

Answer:

resistance is 1.5 ohms (1.5 Ω)

Step-by-step explanation:

R varies directly with l

R varies inversely with $d^2$

We can set-up a proportionality statement as shown below:

$R=k\frac{l}{d^2}$

Now, Given,

R = 1.50

l = 2

d = 1.5

We substitute and find k (the proportionality constant):

$R=k\frac{l}{d^2}\\1.5=k\frac{2}{1.5^2}\\1.5=\frac{2k}{2.25}\\2k=1.5*2.25\\2k=3.375\\k=1.6875$

Now, we will use this value of k to solve the problem.

Given,

l = 8

d = 3

and

k = 1.6875

We find R:

$R=k\frac{l}{d^2}\\R=1.6875\frac{8}{3^2}\\R=\frac{1.6875*8}{9}\\R=1.5$

The resistance is 1.5 ohms (1.5 Ω)

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3 years ago

What is 5 4/6 as an improper fraction?

shtirl [24]

34/6. You do 5 x the 6, then add the 4

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3 years ago

Read 2 more answers

a boat travels upstream on the allegheny river for 2 hours. the return trip only takes 1.7 hours because the boat travels 2.5 mi

Gre4nikov [31]

To solve this we are going to use the speed equation: $S= \frac{d}{t}$
where
$S$ is speed
$d$ is distance
$t$ time

We know from our problem that the upstream trip takes 2 hours, so $t_{u}=2$ . We also know that the downstream trip takes 1.7 hours, so $t_{d}=1.7$ . Notice that the distance of both trips is the same, so we are going to use $d$ to represent that distance.
Now, lets use our equation to relate the quantities:

For the upstream trip:
$S_{u}= \frac{d}{t_{u} }$
$S_{u}= \frac{d}{2}$ equation (1)

For the downstream trip:
$S_{d}= \frac{d}{t_{d} }$
$S_{d}= \frac{d}{1.7}$ equation (2)

We know that the boat travels 2.5 miles per hour faster downstream, so the speed of the boat upstream will be the speed of the boat downstream minus 2.5 miles per hour:
$S_{u}=S_{d}-2.5$ equation (3)

Replacing (3) in (1):
$S_{u}= \frac{d}{2}$
$S_{d}-2.5= \frac{d}{2}$ equation (4)

Solving for $d$ in equation (2):
$S_{d}= \frac{d}{1.7}$
$d=1.7S_{d}$ equation (5)

Replacing (5) in (4):
$S_{d}-2.5= \frac{d}{2}$
$S_{d}-2.5= \frac{1.7S_{d}}{2}$
$2(S_{d}-2.5)=1.7S_{d}$
$2S_{d}-5=1.7S_{d}$
$0.3S_{d}=5$
$S__{d}= \frac{5}{0.3}$
$S_{d}= \frac{50}{3}$ equation (6)

Replacing (6) in (5)
$d=1.7S_{d}$
$d=1.7( \frac{50}{3} )$
$d= \frac{85}{3}$ miles

We can conclude that the boat travel $\frac{85}{3}$ , which is approximately 28.3 miles, in one way.

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3 years ago

Who has the answers I need it

Allisa [31]

Answer:

$\sqrt{(2 \sqrt{34} ) {}^{2} - (6) {}^{2} }$

Step-by-step explanation:

theorem of Pythagoras

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3 years ago