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Tomtit [17]
3 years ago
13

I NEED HELP PLZ(what's the answer????)

Mathematics
1 answer:
kogti [31]3 years ago
4 0

Answer: c

Step-by-step explanation:

Multiply the diameter by pi. You got it right

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What is the simplest radical form of the expression?
Anna35 [415]

Answer:

x^2y^2 3y^2

Step-by-step explanation:

its a or the first choice

6 0
3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
3 years ago
Plzz answer will give you brainliest!!!
Papessa [141]

Answer:

I think C

Step-by-step explanation:

Hope it was Right.

4 0
3 years ago
Read 2 more answers
Maria ran 194 miles in 4 hours.What is the unit rate
astraxan [27]
The unit rate would be 48.5 miles per hour because you would just divide 194 and 4 and get the ratio of 48.5:1
4 0
3 years ago
Read 2 more answers
The Yankees won 125 games, the Red Sox won 97 games, and the Mets won 86 games.
marin [14]

Answer:

127:97:86

Step-by-step explanation:

The yankees won 125 games

The Red Sox won 97 games.

The Mets won 86 games

Therefore the ratio of wins of the Yankees to the red Sox to the Mets can be shown as follows

127:97:86

4 0
3 years ago
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