Ask question

Ask question

All categories

3 years ago

5

30 movies were rented by 5 people. This is the same ratio as 3 people renting ___ movies.

2 answers:

fomenos3 years ago

6 0

3 people rent 18 movies altogether. I person would rent 6 movies

Leto [7]3 years ago

6 0

3 people rent 18 movies.

You might be interested in

In the example at the top of page 384, of the park was 1/8 mile from baseball practice instead of 1/3 mile, how far would Alex r

MrMuchimi

Ghggggggggggggggggggggg

6 0

3 years ago

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

5 0

3 years ago

1 and 3/4 times 1 and 1/3

Orlov [11]

Answer:

7/3

Step-by-step explanation:

Simplify the following:

(1 + 3/4) (1 + 1/3)

Hint: | Put the fractions in 1 + 1/3 over a common denominator.

Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:

(1 + 3/4) 3/3 + 1/3

Hint: | Add the fractions over a common denominator to a single fraction.

3/3 + 1/3 = (3 + 1)/3:

(1 + 3/4) (3 + 1)/3

Hint: | Evaluate 3 + 1.

3 + 1 = 4:

(1 + 3/4)×4/3

Hint: | Put the fractions in 1 + 3/4 over a common denominator.

Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:

4/3 4/4 + 3/4

Hint: | Add the fractions over a common denominator to a single fraction.

4/4 + 3/4 = (4 + 3)/4:

4/3 (4 + 3)/4

Hint: | Evaluate 4 + 3.

4 + 3 = 7:

7/4×4/3

Hint: | Express 7/4×4/3 as a single fraction.

7/4×4/3 = (7×4)/(4×3):

(7×4)/(4×3)

Hint: | Cancel common terms in the numerator and denominator of (7×4)/(4×3).

(7×4)/(4×3) = 4/4×7/3 = 7/3:

Answer: 7/3

8 0

3 years ago

Read 2 more answers

Will mark BRAINLIEST!!!

Irina18 [472]

Answer:

the 2nd one is correct

Step-by-step explanation:

8 0

3 years ago

A client would like this logo printed onto a canvas that is at least 70 inches tall. The original logo is 4.5 inches wide by 3.6

vfiekz [6]

Answer:

87.5 by 70 inches

Step-by-step explanation:

No options were given. So, I will calculate the minimum width

Given

$Original\ Logo = 4.5 : 3.6$

Height = 70 in ---- of the printed logo

Required

Determine the dimension that keeps the requirement

Let x be the width of the printed logo.

So, the ratio can be represented as:

$Printed\ Logo = x : 70$

Equate both ratios

$x : 70 = 4.5 : 3.6$

As fraction

$x / 70 = 4.5 / 3.6$

Multiply through by 70

$70 * x / 70 = 4.5 / 3.6* 70$

$x = 87.5$

So, one of the dimension that meets the requirement is a width of 87.5 inches

4 0

3 years ago