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Setler79 [48]
2 years ago
8

Question down below?

Mathematics
2 answers:
Leokris [45]2 years ago
7 0

Answer:

:D

The first and second m.eme LM.AO

Step-by-step explanation:

Whitepunk [10]2 years ago
6 0
Lolzzzzz that’s cool haha
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PLEASE HELP ASAP PLEASE​
shutvik [7]

Answer:

-5.5

Step-by-step explanation:

<em>-10, -9, -8, -8,</em> -6, -5, <em>-1, 1, 7, 6</em>

3 0
2 years ago
Write the equation if this line below​
Alexxandr [17]

Answer:

Step-by-step explanation:

The first step to finding the equation of this line we must find two points that are on this line.

Two points on the lines are (0,3) and (1,0).

Now we must find the slope:

   slope = \frac{y2-y1}{x2-x1}  = \frac{3 - 0}{0-1} =-3

Now after finding the slope which is -3, now let us put it into the point-slope form using the point (0,3) which is also on the line. You could also use (1,0) in this case, but I am using (0,3).

y-3 = -3(x-0)\\y=-3x +3

Thus the equation is y=-3x +3

Hope that helps!

8 0
3 years ago
50 POINTS PLS DONT JUST WAIST POINTS PLEASE HELP MEEE ANSWEEERRRRR
Arada [10]

Answer:

B

Step-by-step explanation:

4 0
2 years ago
A gravel path is to be built around an 18‘ x 15‘ rectangle garden if the width remains constant how why can the path be if there
Ilia_Sergeevich [38]

Answer:

P = 2*(18 + 13) = 62ft

Now to figure out the width of the path we have to do some geometry. There are 3 basic shapes we will use for the path, they are the 13 ft long rectangle, the 18 ft long rectangle, and the squares formed at the corners. These squares' areas are equal to the width squared, whereas the rectangles are only equal to the length times the width. Our total area then becomes:

A = 2*(13*w) + 2*(18*w) + 4*(w*w)

A = 4w^2 + 62w

And since we know the available area is 516 ft^2, putting this in for A and solving the quadratic equation we can get the width:

516 = 4w^2 + 62w

0 = 4w^2 + 62w - 516

Using the quadratic formula: (w = -b2+/-SQRT(b^2 - 4ac)/2a, where a = 4, b = 62, and c = -516)

w = 6, -21.5

Since we obviously cannot have a negative width, 6 must be our answer. Therefore the path can be 6 feet wide!

We can check this answer by doing the following. Please note that by having a 6ft wide path you would actually be adding 12 ft to both dimensions, since you add 6 feet of length to both sides. Your total area would then become:

18+(2*6) x 13+(2*6) = 30x25 = 750 ft^2

Subtracting the area of the garden gives you the are of the gravel required:

750ft^2 - (18*13)ft^2 = 516ft^2

Therefore a width of 6 feet is correct.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the length of a rectangle if the width is
Anna11 [10]

Answer:

What is the length of a rectangle if the width is

10 centimeters and the diagonal is 16 centimeters?

Step-by-step explanation:

8 0
2 years ago
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